Base | Representation |
---|---|
bin | 10110011000001011… |
… | …11001010010011111 |
3 | 1011000021112001200022 |
4 | 23030011321102133 |
5 | 144101043011111 |
6 | 5304050222355 |
7 | 603501405311 |
oct | 131405712237 |
9 | 34007461608 |
10 | 12014032031 |
11 | 51056760a1 |
12 | 23b35849bb |
13 | 11960386c1 |
14 | 81d8317b1 |
15 | 4a4ae32db |
hex | 2cc17949f |
12014032031 has 2 divisors, whose sum is σ = 12014032032. Its totient is φ = 12014032030.
The previous prime is 12014031983. The next prime is 12014032033. The reversal of 12014032031 is 13023041021.
It is a strong prime.
It is an emirp because it is prime and its reverse (13023041021) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12014032031 is a prime.
It is a super-2 number, since 2×120140320312 (a number of 21 digits) contains 22 as substring.
Together with 12014032033, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12014032033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007016015 + 6007016016.
It is an arithmetic number, because the mean of its divisors is an integer number (6007016016).
Almost surely, 212014032031 is an apocalyptic number.
12014032031 is a deficient number, since it is larger than the sum of its proper divisors (1).
12014032031 is an equidigital number, since it uses as much as digits as its factorization.
12014032031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 12014032031 its reverse (13023041021), we get a palindrome (25037073052).
The spelling of 12014032031 in words is "twelve billion, fourteen million, thirty-two thousand, thirty-one".
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