Base | Representation |
---|---|
bin | 1010111011010011111100… |
… | …0000100110001100000101 |
3 | 1120112112102221022010112202 |
4 | 2232310333000212030011 |
5 | 3033314314121213231 |
6 | 41315105323124245 |
7 | 2346663055363151 |
oct | 256647700461405 |
9 | 46475387263482 |
10 | 12014080647941 |
11 | 3912163357029 |
12 | 14204ab373685 |
13 | 691bcc927a28 |
14 | 2d76ada8a061 |
15 | 15c7a91845cb |
hex | aed3f026305 |
12014080647941 has 2 divisors, whose sum is σ = 12014080647942. Its totient is φ = 12014080647940.
The previous prime is 12014080647929. The next prime is 12014080647997. The reversal of 12014080647941 is 14974608041021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9299755202500 + 2714325445441 = 3049550^2 + 1647521^2 .
It is a cyclic number.
It is not a de Polignac number, because 12014080647941 - 234 = 11996900778757 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12014080647901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007040323970 + 6007040323971.
It is an arithmetic number, because the mean of its divisors is an integer number (6007040323971).
Almost surely, 212014080647941 is an apocalyptic number.
It is an amenable number.
12014080647941 is a deficient number, since it is larger than the sum of its proper divisors (1).
12014080647941 is an equidigital number, since it uses as much as digits as its factorization.
12014080647941 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 387072, while the sum is 47.
Adding to 12014080647941 its reverse (14974608041021), we get a palindrome (26988688688962).
The spelling of 12014080647941 in words is "twelve trillion, fourteen billion, eighty million, six hundred forty-seven thousand, nine hundred forty-one".
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