Base | Representation |
---|---|
bin | 1010111011010101010000… |
… | …0101111000110100000111 |
3 | 1120112120100120212101110021 |
4 | 2232311110011320310013 |
5 | 3033321030143401422 |
6 | 41315204400240011 |
7 | 2350004612014333 |
oct | 256652405706407 |
9 | 46476316771407 |
10 | 12014434356487 |
11 | 3912324a84542 |
12 | 1420589910007 |
13 | 691c57cabc24 |
14 | 2d7704a407c3 |
15 | 15c7ca251dc7 |
hex | aed54178d07 |
12014434356487 has 2 divisors, whose sum is σ = 12014434356488. Its totient is φ = 12014434356486.
The previous prime is 12014434356481. The next prime is 12014434356503. The reversal of 12014434356487 is 78465343441021.
It is a happy number.
12014434356487 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12014434356487 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12014434356481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6007217178243 + 6007217178244.
It is an arithmetic number, because the mean of its divisors is an integer number (6007217178244).
Almost surely, 212014434356487 is an apocalyptic number.
12014434356487 is a deficient number, since it is larger than the sum of its proper divisors (1).
12014434356487 is an equidigital number, since it uses as much as digits as its factorization.
12014434356487 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7741440, while the sum is 52.
The spelling of 12014434356487 in words is "twelve trillion, fourteen billion, four hundred thirty-four million, three hundred fifty-six thousand, four hundred eighty-seven".
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