1201453125 has 84 divisors (see below), whose sum is σ = 2143097568. Its totient is φ = 598500000.

The previous prime is 1201453117. The next prime is 1201453157. The reversal of 1201453125 is 5213541021.

It is a happy number.

It is not a de Polignac number, because 1201453125 - 2³ = 1201453117 is a prime.

It is a super-2 number, since 2×1201453125² = 2886979223144531250, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1201453095 and 1201453104.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 83 ways as a sum of consecutive naturals, for example, 16921840 + ... + 16921910.

Almost surely, 2^1201453125 is an apocalyptic number.

1201453125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

1201453125 is a deficient number, since it is larger than the sum of its proper divisors (941644443).

1201453125 is an frugal number, since it uses more digits than its factorization.

1201453125 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 142 (or 98 counting only the distinct ones).

The product of its (nonzero) digits is 1200, while the sum is 24.

The square root of 1201453125 is about 34661.9838584003. The cubic root of 1201453125 is about 1063.0873338638.

Adding to 1201453125 its reverse (5213541021), we get a palindrome (6414994146).

The spelling of 1201453125 in words is "one billion, two hundred one million, four hundred fifty-three thousand, one hundred twenty-five".