120150314400247 has 2 divisors, whose sum is σ = 120150314400248. Its totient is φ = 120150314400246.

The previous prime is 120150314400199. The next prime is 120150314400301. The reversal of 120150314400247 is 742004413051021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 120150314400247 - 2¹¹ = 120150314398199 is a prime.

It is a super-2 number, since 2×120150314400247² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120150314430247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60075157200123 + 60075157200124.

It is an arithmetic number, because the mean of its divisors is an integer number (60075157200124).

Almost surely, 2^{120150314400247} is an apocalyptic number.

120150314400247 is a deficient number, since it is larger than the sum of its proper divisors (1).

120150314400247 is an equidigital number, since it uses as much as digits as its factorization.

120150314400247 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 26880, while the sum is 34.

Adding to 120150314400247 its reverse (742004413051021), we get a palindrome (862154727451268).

The spelling of 120150314400247 in words is "one hundred twenty trillion, one hundred fifty billion, three hundred fourteen million, four hundred thousand, two hundred forty-seven".