Base | Representation |
---|---|
bin | 11011010100011100101010… |
… | …111011011101010101110111 |
3 | 120202102110102110100101011102 |
4 | 123110130222323131111313 |
5 | 111222034134131212401 |
6 | 1103313133044000315 |
7 | 34210504142515211 |
oct | 3324345273352567 |
9 | 522373373311142 |
10 | 120152430335351 |
11 | 353143a5614277 |
12 | 1158641999009b |
13 | 520743035658b |
14 | 21955a14d95b1 |
15 | dd569179e56b |
hex | 6d472aedd577 |
120152430335351 has 2 divisors, whose sum is σ = 120152430335352. Its totient is φ = 120152430335350.
The previous prime is 120152430335341. The next prime is 120152430335383. The reversal of 120152430335351 is 153533034251021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120152430335351 - 222 = 120152426141047 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120152430335341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60076215167675 + 60076215167676.
It is an arithmetic number, because the mean of its divisors is an integer number (60076215167676).
Almost surely, 2120152430335351 is an apocalyptic number.
120152430335351 is a deficient number, since it is larger than the sum of its proper divisors (1).
120152430335351 is an equidigital number, since it uses as much as digits as its factorization.
120152430335351 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 162000, while the sum is 38.
Adding to 120152430335351 its reverse (153533034251021), we get a palindrome (273685464586372).
The spelling of 120152430335351 in words is "one hundred twenty trillion, one hundred fifty-two billion, four hundred thirty million, three hundred thirty-five thousand, three hundred fifty-one".
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