120171251151670 has 32 divisors (see below), whose sum is σ = 216763637068800. Its totient is φ = 47967307319136.

The previous prime is 120171251151659. The next prime is 120171251151737. The reversal of 120171251151670 is 76151152171021.

It is a super-3 number, since 3×120171251151670³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 322214161 + ... + 322586899.

It is an arithmetic number, because the mean of its divisors is an integer number (6773863658400).

Almost surely, 2^{120171251151670} is an apocalyptic number.

120171251151670 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

120171251151670 is a deficient number, since it is larger than the sum of its proper divisors (96592385917130).

120171251151670 is a wasteful number, since it uses less digits than its factorization.

120171251151670 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 440532.

The product of its (nonzero) digits is 29400, while the sum is 40.

The spelling of 120171251151670 in words is "one hundred twenty trillion, one hundred seventy-one billion, two hundred fifty-one million, one hundred fifty-one thousand, six hundred seventy".