1201720130 has 48 divisors (see below), whose sum is σ = 2380890024. Its totient is φ = 436400640.

The previous prime is 1201720129. The next prime is 1201720133. The reversal of 1201720130 is 310271021.

It can be written as a sum of positive squares in 12 ways, for example, as 73633561 + 1128086569 = 8581^2 + 33587^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1201720099 and 1201720108.

It is not an unprimeable number, because it can be changed into a prime (1201720133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 97262 + ... + 108918.

Almost surely, 2^1201720130 is an apocalyptic number.

1201720130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1201720130 is a deficient number, since it is larger than the sum of its proper divisors (1179169894).

1201720130 is a wasteful number, since it uses less digits than its factorization.

1201720130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11751 (or 11738 counting only the distinct ones).

The product of its (nonzero) digits is 84, while the sum is 17.

The square root of 1201720130 is about 34665.8351983621. The cubic root of 1201720130 is about 1063.1660797877.

Adding to 1201720130 its reverse (310271021), we get a palindrome (1511991151).

The spelling of 1201720130 in words is "one billion, two hundred one million, seven hundred twenty thousand, one hundred thirty".