Base | Representation |
---|---|
bin | 10110011000111011… |
… | …10101001000100110 |
3 | 1011000201022211120221 |
4 | 23030131311020212 |
5 | 144104144301340 |
6 | 5304432514554 |
7 | 603605630164 |
oct | 131435651046 |
9 | 34021284527 |
10 | 12020306470 |
11 | 5109171187 |
12 | 23b56aba5a |
13 | 11974245a3 |
14 | 8205c6234 |
15 | 4a543244a |
hex | 2cc775226 |
12020306470 has 8 divisors (see below), whose sum is σ = 21636551664. Its totient is φ = 4808122584.
The previous prime is 12020306449. The next prime is 12020306477. The reversal of 12020306470 is 7460302021.
12020306470 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12020306477) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 601015314 + ... + 601015333.
It is an arithmetic number, because the mean of its divisors is an integer number (2704568958).
Almost surely, 212020306470 is an apocalyptic number.
12020306470 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12020306470 is a deficient number, since it is larger than the sum of its proper divisors (9616245194).
12020306470 is a wasteful number, since it uses less digits than its factorization.
12020306470 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1202030654.
The product of its (nonzero) digits is 2016, while the sum is 25.
Adding to 12020306470 its reverse (7460302021), we get a palindrome (19480608491).
The spelling of 12020306470 in words is "twelve billion, twenty million, three hundred six thousand, four hundred seventy".
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