Base | Representation |
---|---|
bin | 1010111011101011001100… |
… | …0101101101010001110101 |
3 | 1120120010112222121011110021 |
4 | 2232322303011231101311 |
5 | 3033420110204041203 |
6 | 41322021000525141 |
7 | 2350303545426034 |
oct | 256726305552165 |
9 | 46503488534407 |
10 | 12020323112053 |
11 | 3914877033783 |
12 | 1421751a807b1 |
13 | 692685cc8089 |
14 | 2d7b02b7271b |
15 | 15ca222135bd |
hex | aeeb316d475 |
12020323112053 has 2 divisors, whose sum is σ = 12020323112054. Its totient is φ = 12020323112052.
The previous prime is 12020323112041. The next prime is 12020323112113. The reversal of 12020323112053 is 35021132302021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10633220983044 + 1387102129009 = 3260862^2 + 1177753^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12020323112053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12020323112653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010161556026 + 6010161556027.
It is an arithmetic number, because the mean of its divisors is an integer number (6010161556027).
Almost surely, 212020323112053 is an apocalyptic number.
It is an amenable number.
12020323112053 is a deficient number, since it is larger than the sum of its proper divisors (1).
12020323112053 is an equidigital number, since it uses as much as digits as its factorization.
12020323112053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 12020323112053 its reverse (35021132302021), we get a palindrome (47041455414074).
The spelling of 12020323112053 in words is "twelve trillion, twenty billion, three hundred twenty-three million, one hundred twelve thousand, fifty-three".
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