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1202100132022 = 2601050066011
BaseRepresentation
bin10001011111100010110…
…000000101100010110110
311020220211102110212111221
4101133202300011202312
5124143400113211042
62320123121420554
7152564106346636
oct21374260054266
94226742425457
101202100132022
11423898205399
12174b84a9a75a
138948572098a
144227940a6c6
152140927bd67
hex117e2c058b6

1202100132022 has 4 divisors (see below), whose sum is σ = 1803150198036. Its totient is φ = 601050066010.

The previous prime is 1202100132017. The next prime is 1202100132061. The reversal of 1202100132022 is 2202310012021.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 1202100131987 and 1202100132005.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 300525033004 + ... + 300525033007.

It is an arithmetic number, because the mean of its divisors is an integer number (450787549509).

Almost surely, 21202100132022 is an apocalyptic number.

1202100132022 is a deficient number, since it is larger than the sum of its proper divisors (601050066014).

1202100132022 is an equidigital number, since it uses as much as digits as its factorization.

1202100132022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 601050066013.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 1202100132022 its reverse (2202310012021), we get a palindrome (3404410144043).

The spelling of 1202100132022 in words is "one trillion, two hundred two billion, one hundred million, one hundred thirty-two thousand, twenty-two".

Divisors: 1 2 601050066011 1202100132022