Base | Representation |
---|---|
bin | 1010111011101110000110… |
… | …0000111011011101101111 |
3 | 1120120012120021012202211101 |
4 | 2232323201200323131233 |
5 | 3033423204102444413 |
6 | 41322230143103531 |
7 | 2350332054032236 |
oct | 256734140733557 |
9 | 46505507182741 |
10 | 12021101999983 |
11 | 391513676480a |
12 | 142192a8a1ba7 |
13 | 69277b4985cb |
14 | 2d7b783a3b1d |
15 | 15ca6a7b9edd |
hex | aeee183b76f |
12021101999983 has 2 divisors, whose sum is σ = 12021101999984. Its totient is φ = 12021101999982.
The previous prime is 12021101999971. The next prime is 12021102000029. The reversal of 12021101999983 is 38999910112021.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12021101999983 - 217 = 12021101868911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12021101999083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010550999991 + 6010550999992.
It is an arithmetic number, because the mean of its divisors is an integer number (6010550999992).
Almost surely, 212021101999983 is an apocalyptic number.
12021101999983 is a deficient number, since it is larger than the sum of its proper divisors (1).
12021101999983 is an equidigital number, since it uses as much as digits as its factorization.
12021101999983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 629856, while the sum is 55.
The spelling of 12021101999983 in words is "twelve trillion, twenty-one billion, one hundred one million, nine hundred ninety-nine thousand, nine hundred eighty-three".
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