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1202122000133 is a prime number
BaseRepresentation
bin10001011111100100000…
…011100000011100000101
311020220212221121212220222
4101133210003200130011
5124143421213001013
62320125222234125
7152564463256235
oct21374403403405
94226787555828
101202122000133
114238a959120a
12174b90285945
138948a1094a2
144227c29dcc5
152140b14b508
hex117e40e0705

1202122000133 has 2 divisors, whose sum is σ = 1202122000134. Its totient is φ = 1202122000132.

The previous prime is 1202122000117. The next prime is 1202122000139. The reversal of 1202122000133 is 3310002212021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1147088124484 + 55033875649 = 1071022^2 + 234593^2 .

It is an emirp because it is prime and its reverse (3310002212021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1202122000133 - 24 = 1202122000117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1202122000139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601061000066 + 601061000067.

It is an arithmetic number, because the mean of its divisors is an integer number (601061000067).

Almost surely, 21202122000133 is an apocalyptic number.

It is an amenable number.

1202122000133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1202122000133 is an equidigital number, since it uses as much as digits as its factorization.

1202122000133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 1202122000133 its reverse (3310002212021), we get a palindrome (4512124212154).

The spelling of 1202122000133 in words is "one trillion, two hundred two billion, one hundred twenty-two million, one hundred thirty-three", and thus it is an aban number.