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1202122000117 is a prime number
BaseRepresentation
bin10001011111100100000…
…011100000011011110101
311020220212221121212220101
4101133210003200123311
5124143421213000432
62320125222234101
7152564463256213
oct21374403403365
94226787555811
101202122000117
114238a95911a5
12174b90285931
138948a10948c
144227c29dcb3
152140b14b4e7
hex117e40e06f5

1202122000117 has 2 divisors, whose sum is σ = 1202122000118. Its totient is φ = 1202122000116.

The previous prime is 1202122000097. The next prime is 1202122000133. The reversal of 1202122000117 is 7110002212021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 790745999121 + 411376000996 = 889239^2 + 641386^2 .

It is a cyclic number.

It is not a de Polignac number, because 1202122000117 - 231 = 1199974516469 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1202122000094 and 1202122000103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1202122000817) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601061000058 + 601061000059.

It is an arithmetic number, because the mean of its divisors is an integer number (601061000059).

Almost surely, 21202122000117 is an apocalyptic number.

It is an amenable number.

1202122000117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1202122000117 is an equidigital number, since it uses as much as digits as its factorization.

1202122000117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 112, while the sum is 19.

Adding to 1202122000117 its reverse (7110002212021), we get a palindrome (8312124212138).

The spelling of 1202122000117 in words is "one trillion, two hundred two billion, one hundred twenty-two million, one hundred seventeen", and thus it is an aban number.