Base | Representation |
---|---|
bin | 110111111110101000… |
… | …0101011000000111011 |
3 | 102111021212012101110202 |
4 | 1233331100223000323 |
5 | 3432144024420011 |
6 | 131120344232415 |
7 | 11453664454433 |
oct | 1577520530073 |
9 | 374255171422 |
10 | 120213123131 |
11 | 46a891a0742 |
12 | 1b36b16b70b |
13 | b44a3b792a |
14 | 5b657832c3 |
15 | 31d8a5323b |
hex | 1bfd42b03b |
120213123131 has 2 divisors, whose sum is σ = 120213123132. Its totient is φ = 120213123130.
The previous prime is 120213123071. The next prime is 120213123133. The reversal of 120213123131 is 131321312021.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (131321312021) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120213123131 is a prime.
It is a super-2 number, since 2×1202131231312 (a number of 23 digits) contains 22 as substring.
Together with 120213123133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (120213123133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60106561565 + 60106561566.
It is an arithmetic number, because the mean of its divisors is an integer number (60106561566).
Almost surely, 2120213123131 is an apocalyptic number.
120213123131 is a deficient number, since it is larger than the sum of its proper divisors (1).
120213123131 is an equidigital number, since it uses as much as digits as its factorization.
120213123131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 120213123131 its reverse (131321312021), we get a palindrome (251534435152).
The spelling of 120213123131 in words is "one hundred twenty billion, two hundred thirteen million, one hundred twenty-three thousand, one hundred thirty-one".
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