12021332880407 has 2 divisors, whose sum is σ = 12021332880408. Its totient is φ = 12021332880406.

The previous prime is 12021332880311. The next prime is 12021332880409. The reversal of 12021332880407 is 70408823312021.

It is a strong prime.

It is an emirp because it is prime and its reverse (70408823312021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12021332880407 is a prime.

Together with 12021332880409, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12021332880409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010666440203 + 6010666440204.

It is an arithmetic number, because the mean of its divisors is an integer number (6010666440204).

Almost surely, 2^{12021332880407} is an apocalyptic number.

12021332880407 is a deficient number, since it is larger than the sum of its proper divisors (1).

12021332880407 is an equidigital number, since it uses as much as digits as its factorization.

12021332880407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129024, while the sum is 41.

The spelling of 12021332880407 in words is "twelve trillion, twenty-one billion, three hundred thirty-two million, eight hundred eighty thousand, four hundred seven".