Base | Representation |
---|---|
bin | 1010111011110001011100… |
… | …0010100110101000100111 |
3 | 1120120021212211222220201021 |
4 | 2232330113002212220213 |
5 | 3033432024001120012 |
6 | 41322455222512011 |
7 | 2350363240053355 |
oct | 256742702465047 |
9 | 46507784886637 |
10 | 12022000020007 |
11 | 391555766451a |
12 | 1421b3b595607 |
13 | 69289254a9c3 |
14 | 2d7c217667d5 |
15 | 15cabe555007 |
hex | aef170a6a27 |
12022000020007 has 2 divisors, whose sum is σ = 12022000020008. Its totient is φ = 12022000020006.
The previous prime is 12022000019969. The next prime is 12022000020011. The reversal of 12022000020007 is 70002000022021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12022000020007 - 219 = 12021999495719 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12022000020067) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011000010003 + 6011000010004.
It is an arithmetic number, because the mean of its divisors is an integer number (6011000010004).
Almost surely, 212022000020007 is an apocalyptic number.
12022000020007 is a deficient number, since it is larger than the sum of its proper divisors (1).
12022000020007 is an equidigital number, since it uses as much as digits as its factorization.
12022000020007 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 16.
Adding to 12022000020007 its reverse (70002000022021), we get a palindrome (82024000042028).
The spelling of 12022000020007 in words is "twelve trillion, twenty-two billion, twenty thousand, seven".
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