12022100113 has 2 divisors, whose sum is σ = 12022100114. Its totient is φ = 12022100112.

The previous prime is 12022100093. The next prime is 12022100179. The reversal of 12022100113 is 31100122021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11519084929 + 503015184 = 107327^2 + 22428^2 .

It is a cyclic number.

It is not a de Polignac number, because 12022100113 - 2²⁹ = 11485229201 is a prime.

It is a super-2 number, since 2×12022100113² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12022100093 and 12022100102.

It is not a weakly prime, because it can be changed into another prime (12022100513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011050056 + 6011050057.

It is an arithmetic number, because the mean of its divisors is an integer number (6011050057).

Almost surely, 2^12022100113 is an apocalyptic number.

It is an amenable number.

12022100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12022100113 is an equidigital number, since it uses as much as digits as its factorization.

12022100113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 12022100113 its reverse (31100122021), we get a palindrome (43122222134).

The spelling of 12022100113 in words is "twelve billion, twenty-two million, one hundred thousand, one hundred thirteen".