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12022100513 is a prime number
BaseRepresentation
bin10110011001001001…
…01011001000100001
31011000211200222112222
423030210223020201
5144110124204023
65304535200425
7603630111503
oct131444531041
934024628488
1012022100513
11510a187065
1223b6216115
131197902057
14820931d73
154a5688cc8
hex2cc92b221

12022100513 has 2 divisors, whose sum is σ = 12022100514. Its totient is φ = 12022100512.

The previous prime is 12022100501. The next prime is 12022100537. The reversal of 12022100513 is 31500122021.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11852241424 + 169859089 = 108868^2 + 13033^2 .

It is a cyclic number.

It is not a de Polignac number, because 12022100513 - 226 = 11954991649 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12022100491 and 12022100500.

It is not a weakly prime, because it can be changed into another prime (12022100113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011050256 + 6011050257.

It is an arithmetic number, because the mean of its divisors is an integer number (6011050257).

Almost surely, 212022100513 is an apocalyptic number.

It is an amenable number.

12022100513 is a deficient number, since it is larger than the sum of its proper divisors (1).

12022100513 is an equidigital number, since it uses as much as digits as its factorization.

12022100513 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120, while the sum is 17.

Adding to 12022100513 its reverse (31500122021), we get a palindrome (43522222534).

The spelling of 12022100513 in words is "twelve billion, twenty-two million, one hundred thousand, five hundred thirteen".