Base | Representation |
---|---|
bin | 1010111011110001110110… |
… | …0110111010000110001011 |
3 | 1120120022011112022122112021 |
4 | 2232330131212322012023 |
5 | 3033432240202401303 |
6 | 41322514200225311 |
7 | 2350366045425415 |
oct | 256743546720613 |
9 | 46508145278467 |
10 | 12022110200203 |
11 | 3915603879534 |
12 | 1421b7046b237 |
13 | 6928ac31709c |
14 | 2d7c322479b5 |
15 | 15cac906aebd |
hex | aef1d9ba18b |
12022110200203 has 2 divisors, whose sum is σ = 12022110200204. Its totient is φ = 12022110200202.
The previous prime is 12022110200183. The next prime is 12022110200257. The reversal of 12022110200203 is 30200201122021.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12022110200203 - 229 = 12021573329291 is a prime.
It is a super-3 number, since 3×120221102002033 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (12022110200273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011055100101 + 6011055100102.
It is an arithmetic number, because the mean of its divisors is an integer number (6011055100102).
Almost surely, 212022110200203 is an apocalyptic number.
12022110200203 is a deficient number, since it is larger than the sum of its proper divisors (1).
12022110200203 is an equidigital number, since it uses as much as digits as its factorization.
12022110200203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 12022110200203 its reverse (30200201122021), we get a palindrome (42222311322224).
The spelling of 12022110200203 in words is "twelve trillion, twenty-two billion, one hundred ten million, two hundred thousand, two hundred three".
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