Base | Representation |
---|---|
bin | 11011010101011100110100… |
… | …000100010000000111000110 |
3 | 120202200001012022121221110222 |
4 | 123111130310010100013012 |
5 | 111224201212044042014 |
6 | 1103404523150344342 |
7 | 34215462651456620 |
oct | 3325346404200706 |
9 | 522601168557428 |
10 | 120221303112134 |
11 | 35340628497904 |
12 | 1159783b1bb0b2 |
13 | 5210a880ab133 |
14 | 2198a56527c10 |
15 | dd7372e4d08e |
hex | 6d57341101c6 |
120221303112134 has 64 divisors (see below), whose sum is σ = 211282962250752. Its totient is φ = 50228039347200.
The previous prime is 120221303112121. The next prime is 120221303112137. The reversal of 120221303112134 is 431211303122021.
It is a super-3 number, since 3×1202213031121343 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120221303112137) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6643152974 + ... + 6643171070.
It is an arithmetic number, because the mean of its divisors is an integer number (3301296285168).
Almost surely, 2120221303112134 is an apocalyptic number.
120221303112134 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
120221303112134 is a deficient number, since it is larger than the sum of its proper divisors (91061659138618).
120221303112134 is a wasteful number, since it uses less digits than its factorization.
120221303112134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26421.
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 120221303112134 its reverse (431211303122021), we get a palindrome (551432606234155).
The spelling of 120221303112134 in words is "one hundred twenty trillion, two hundred twenty-one billion, three hundred three million, one hundred twelve thousand, one hundred thirty-four".
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