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120221303112137 is a prime number
BaseRepresentation
bin11011010101011100110100…
…000100010000000111001001
3120202200001012022121221111002
4123111130310010100013021
5111224201212044042022
61103404523150344345
734215462651456623
oct3325346404200711
9522601168557432
10120221303112137
1135340628497907
121159783b1bb0b5
135210a880ab136
142198a56527c13
15dd7372e4d092
hex6d57341101c9

120221303112137 has 2 divisors, whose sum is σ = 120221303112138. Its totient is φ = 120221303112136.

The previous prime is 120221303112121. The next prime is 120221303112139. The reversal of 120221303112137 is 731211303122021.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109469849030656 + 10751454081481 = 10462784^2 + 3278941^2 .

It is a cyclic number.

It is not a de Polignac number, because 120221303112137 - 24 = 120221303112121 is a prime.

Together with 120221303112139, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (120221303112139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60110651556068 + 60110651556069.

It is an arithmetic number, because the mean of its divisors is an integer number (60110651556069).

Almost surely, 2120221303112137 is an apocalyptic number.

It is an amenable number.

120221303112137 is a deficient number, since it is larger than the sum of its proper divisors (1).

120221303112137 is an equidigital number, since it uses as much as digits as its factorization.

120221303112137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3024, while the sum is 29.

Adding to 120221303112137 its reverse (731211303122021), we get a palindrome (851432606234158).

The spelling of 120221303112137 in words is "one hundred twenty trillion, two hundred twenty-one billion, three hundred three million, one hundred twelve thousand, one hundred thirty-seven".