Base | Representation |
---|---|
bin | 11011010101011101011110… |
… | …110010111101100011111111 |
3 | 120202200010001021120121202101 |
4 | 123111131132302331203333 |
5 | 111224204144104444444 |
6 | 1103405122240005531 |
7 | 34215516505065661 |
oct | 3325353662754377 |
9 | 522603037517671 |
10 | 120222019999999 |
11 | 35340966121315 |
12 | 115979bb3008a7 |
13 | 5210b70781238 |
14 | 2198ac381a531 |
15 | dd73b5d593d4 |
hex | 6d575ecbd8ff |
120222019999999 has 2 divisors, whose sum is σ = 120222020000000. Its totient is φ = 120222019999998.
The previous prime is 120222019999997. The next prime is 120222020000057. The reversal of 120222019999999 is 999999910222021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120222019999999 - 21 = 120222019999997 is a prime.
Together with 120222019999997, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120222019999997) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60111009999999 + 60111010000000.
It is an arithmetic number, because the mean of its divisors is an integer number (60111010000000).
Almost surely, 2120222019999999 is an apocalyptic number.
120222019999999 is a deficient number, since it is larger than the sum of its proper divisors (1).
120222019999999 is an equidigital number, since it uses as much as digits as its factorization.
120222019999999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 76527504, while the sum is 73.
The spelling of 120222019999999 in words is "one hundred twenty trillion, two hundred twenty-two billion, nineteen million, nine hundred ninety-nine thousand, nine hundred ninety-nine".
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