Base | Representation |
---|---|
bin | 11011010101011101011110… |
… | …110010111101100100010101 |
3 | 120202200010001021120121210012 |
4 | 123111131132302331210111 |
5 | 111224204144110000041 |
6 | 1103405122240010005 |
7 | 34215516505066022 |
oct | 3325353662754425 |
9 | 522603037517705 |
10 | 120222020000021 |
11 | 35340966121335 |
12 | 115979bb300905 |
13 | 5210b70781254 |
14 | 2198ac381a549 |
15 | dd73b5d593eb |
hex | 6d575ecbd915 |
120222020000021 has 24 divisors (see below), whose sum is σ = 135251493933120. Its totient is φ = 106615183352832.
The previous prime is 120222019999999. The next prime is 120222020000057. The reversal of 120222020000021 is 120000020222021.
It is a de Polignac number, because none of the positive numbers 2k-120222020000021 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 120222019999960 and 120222020000005.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120222020000081) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 134529716 + ... + 135420413.
It is an arithmetic number, because the mean of its divisors is an integer number (5635478913880).
Almost surely, 2120222020000021 is an apocalyptic number.
It is an amenable number.
120222020000021 is a deficient number, since it is larger than the sum of its proper divisors (15029473933099).
120222020000021 is a wasteful number, since it uses less digits than its factorization.
120222020000021 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 269950253 (or 269950236 counting only the distinct ones).
The product of its (nonzero) digits is 64, while the sum is 14.
Adding to 120222020000021 its reverse (120000020222021), we get a palindrome (240222040222042).
The spelling of 120222020000021 in words is "one hundred twenty trillion, two hundred twenty-two billion, twenty million, twenty-one", and thus it is an aban number.
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