Base | Representation |
---|---|
bin | 1010111011110101001010… |
… | …1001101010000010110010 |
3 | 1120120101110112211220211201 |
4 | 2232331102221222002302 |
5 | 3033441101012111310 |
6 | 41323142350201414 |
7 | 2350430102523343 |
oct | 256752251520262 |
9 | 46511415756751 |
10 | 12023000113330 |
11 | 3915a20141428 |
12 | 142217a4b326a |
13 | 6929c17bb4bb |
14 | 2d7cb84da0ca |
15 | 15cb2c253e3a |
hex | aef52a6a0b2 |
12023000113330 has 32 divisors (see below), whose sum is σ = 21721898278080. Its totient is φ = 4791344687040.
The previous prime is 12023000113321. The next prime is 12023000113343. The reversal of 12023000113330 is 3331100032021.
12023000113330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 12023000113298 and 12023000113307.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 838017 + ... + 4974763.
It is an arithmetic number, because the mean of its divisors is an integer number (678809321190).
Almost surely, 212023000113330 is an apocalyptic number.
12023000113330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12023000113330 is a deficient number, since it is larger than the sum of its proper divisors (9698898164750).
12023000113330 is a wasteful number, since it uses less digits than its factorization.
12023000113330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4137834.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 12023000113330 its reverse (3331100032021), we get a palindrome (15354100145351).
The spelling of 12023000113330 in words is "twelve trillion, twenty-three billion, one hundred thirteen thousand, three hundred thirty".
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