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120255020433967 is a prime number
BaseRepresentation
bin11011010101111100001101…
…110001101000001000101111
3120202210021020010201100202111
4123111330031301220020233
5111230224240212341332
61103432221013504451
734221065340125506
oct3325741561501057
9522707203640674
10120255020433967
113535395aaa1841
12115a228b042127
135213ccc650243
14219a53454183d
15dd81980b0947
hex6d5f0dc6822f

120255020433967 has 2 divisors, whose sum is σ = 120255020433968. Its totient is φ = 120255020433966.

The previous prime is 120255020433913. The next prime is 120255020434033. The reversal of 120255020433967 is 769334020552021.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 120255020433967 - 215 = 120255020401199 is a prime.

It is a super-2 number, since 2×1202550204339672 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 120255020433967.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120255020433907) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60127510216983 + 60127510216984.

It is an arithmetic number, because the mean of its divisors is an integer number (60127510216984).

Almost surely, 2120255020433967 is an apocalyptic number.

120255020433967 is a deficient number, since it is larger than the sum of its proper divisors (1).

120255020433967 is an equidigital number, since it uses as much as digits as its factorization.

120255020433967 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2721600, while the sum is 49.

Adding to 120255020433967 its reverse (769334020552021), we get a palindrome (889589040985988).

The spelling of 120255020433967 in words is "one hundred twenty trillion, two hundred fifty-five billion, twenty million, four hundred thirty-three thousand, nine hundred sixty-seven".