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120255040351471 is a prime number
BaseRepresentation
bin11011010101111100001110…
…111101100110110011101111
3120202210021021112012021102211
4123111330032331212303233
5111230224310312221341
61103432223004431251
734221066001332154
oct3325741675466357
9522707245167384
10120255040351471
1135353970266093
12115a2295848527
135214003804c4c
14219a53704822b
15dd8199be7181
hex6d5f0ef66cef

120255040351471 has 2 divisors, whose sum is σ = 120255040351472. Its totient is φ = 120255040351470.

The previous prime is 120255040351441. The next prime is 120255040351583. The reversal of 120255040351471 is 174153040552021.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 120255040351471 - 231 = 120252892867823 is a prime.

It is a super-3 number, since 3×1202550403514713 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120255040351441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60127520175735 + 60127520175736.

It is an arithmetic number, because the mean of its divisors is an integer number (60127520175736).

Almost surely, 2120255040351471 is an apocalyptic number.

120255040351471 is a deficient number, since it is larger than the sum of its proper divisors (1).

120255040351471 is an equidigital number, since it uses as much as digits as its factorization.

120255040351471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 168000, while the sum is 40.

The spelling of 120255040351471 in words is "one hundred twenty trillion, two hundred fifty-five billion, forty million, three hundred fifty-one thousand, four hundred seventy-one".