Base | Representation |
---|---|
bin | 11011010110101001001100… |
… | …110101101011001111110111 |
3 | 120202221212220102201001002221 |
4 | 123112221030311223033313 |
5 | 111232022201203201101 |
6 | 1103510330023343211 |
7 | 34224425332042252 |
oct | 3326511465531767 |
9 | 522855812631087 |
10 | 120303323100151 |
11 | 35372397652874 |
12 | 115ab70b5b1b07 |
13 | 5218729868119 |
14 | 219c9d7682099 |
15 | dd957392baa1 |
hex | 6d6a4cd6b3f7 |
120303323100151 has 2 divisors, whose sum is σ = 120303323100152. Its totient is φ = 120303323100150.
The previous prime is 120303323100143. The next prime is 120303323100157. The reversal of 120303323100151 is 151001323303021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120303323100151 - 23 = 120303323100143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120303323100157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60151661550075 + 60151661550076.
It is an arithmetic number, because the mean of its divisors is an integer number (60151661550076).
Almost surely, 2120303323100151 is an apocalyptic number.
120303323100151 is a deficient number, since it is larger than the sum of its proper divisors (1).
120303323100151 is an equidigital number, since it uses as much as digits as its factorization.
120303323100151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1620, while the sum is 25.
Adding to 120303323100151 its reverse (151001323303021), we get a palindrome (271304646403172).
The spelling of 120303323100151 in words is "one hundred twenty trillion, three hundred three billion, three hundred twenty-three million, one hundred thousand, one hundred fifty-one".
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