Base | Representation |
---|---|
bin | 1010111100011110001100… |
… | …0010010111001000011011 |
3 | 1120121102220000111020102121 |
4 | 2233013203002113020123 |
5 | 3034131124141140123 |
6 | 41332203214442111 |
7 | 2351300022011254 |
oct | 257074302271033 |
9 | 46542800436377 |
10 | 12034012443163 |
11 | 391a661330867 |
12 | 1424332503337 |
13 | 693a58141cb9 |
14 | 2d8640c99b2b |
15 | 15d073e2b75d |
hex | af1e309721b |
12034012443163 has 2 divisors, whose sum is σ = 12034012443164. Its totient is φ = 12034012443162.
The previous prime is 12034012443161. The next prime is 12034012443169. The reversal of 12034012443163 is 36134421043021.
12034012443163 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12034012443163 - 21 = 12034012443161 is a prime.
It is a super-3 number, since 3×120340124431633 (a number of 40 digits) contains 333 as substring.
Together with 12034012443161, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (12034012443161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6017006221581 + 6017006221582.
It is an arithmetic number, because the mean of its divisors is an integer number (6017006221582).
Almost surely, 212034012443163 is an apocalyptic number.
12034012443163 is a deficient number, since it is larger than the sum of its proper divisors (1).
12034012443163 is an equidigital number, since it uses as much as digits as its factorization.
12034012443163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 12034012443163 its reverse (36134421043021), we get a palindrome (48168433486184).
The spelling of 12034012443163 in words is "twelve trillion, thirty-four billion, twelve million, four hundred forty-three thousand, one hundred sixty-three".
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