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12040304317 is a prime number
BaseRepresentation
bin10110011011010100…
…00111011010111101
31011002002221211110221
423031222013122331
5144124304214232
65310425301341
7604240620016
oct131552073275
934062854427
1012040304317
11511948a928
122400334851
13119b606a32
1482311000d
154a7082897
hex2cda876bd

12040304317 has 2 divisors, whose sum is σ = 12040304318. Its totient is φ = 12040304316.

The previous prime is 12040304291. The next prime is 12040304323. The reversal of 12040304317 is 71340304021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10647969721 + 1392334596 = 103189^2 + 37314^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12040304317 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12040304291 and 12040304300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12040304357) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6020152158 + 6020152159.

It is an arithmetic number, because the mean of its divisors is an integer number (6020152159).

Almost surely, 212040304317 is an apocalyptic number.

It is an amenable number.

12040304317 is a deficient number, since it is larger than the sum of its proper divisors (1).

12040304317 is an equidigital number, since it uses as much as digits as its factorization.

12040304317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 25.

Adding to 12040304317 its reverse (71340304021), we get a palindrome (83380608338).

The spelling of 12040304317 in words is "twelve billion, forty million, three hundred four thousand, three hundred seventeen".