Base | Representation |
---|---|
bin | 10001100001010101111… |
… | …001101010101001011010 |
3 | 11021002211001200002220110 |
4 | 101201111321222221122 |
5 | 124211324144220010 |
6 | 2321042532505150 |
7 | 152663015222346 |
oct | 21412571525132 |
9 | 4232731602813 |
10 | 1204032023130 |
11 | 424699762812 |
12 | 175423a7b1b6 |
13 | 89702a3c201 |
14 | 423bdc16626 |
15 | 214bdb89120 |
hex | 11855e6aa5a |
1204032023130 has 32 divisors (see below), whose sum is σ = 2889735450624. Its totient is φ = 321068695616.
The previous prime is 1204032023027. The next prime is 1204032023143. The reversal of 1204032023130 is 313202304021.
It is a super-4 number, since 4×12040320231304 (a number of 49 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 1204032023097 and 1204032023106.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1201447 + ... + 1962533.
It is an arithmetic number, because the mean of its divisors is an integer number (90304232832).
Almost surely, 21204032023130 is an apocalyptic number.
1204032023130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1204032023130 is an abundant number, since it is smaller than the sum of its proper divisors (1685703427494).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1204032023130 is a wasteful number, since it uses less digits than its factorization.
1204032023130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 813830.
The product of its (nonzero) digits is 864, while the sum is 21.
Adding to 1204032023130 its reverse (313202304021), we get a palindrome (1517234327151).
The spelling of 1204032023130 in words is "one trillion, two hundred four billion, thirty-two million, twenty-three thousand, one hundred thirty".
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