Base | Representation |
---|---|
bin | 10110011011011100… |
… | …00000011110001111 |
3 | 1011002011212122210221 |
4 | 23031232000132033 |
5 | 144130034340211 |
6 | 5310503212211 |
7 | 604252366063 |
oct | 131556003617 |
9 | 34064778727 |
10 | 12041324431 |
11 | 511a0172a4 |
12 | 2400747067 |
13 | 119b8a3156 |
14 | 8232d7aa3 |
15 | 4a71d4c71 |
hex | 2cdb8078f |
12041324431 has 2 divisors, whose sum is σ = 12041324432. Its totient is φ = 12041324430.
The previous prime is 12041324411. The next prime is 12041324467. The reversal of 12041324431 is 13442314021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12041324431 is a prime.
It is a super-2 number, since 2×120413244312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12041324396 and 12041324405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12041324401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6020662215 + 6020662216.
It is an arithmetic number, because the mean of its divisors is an integer number (6020662216).
Almost surely, 212041324431 is an apocalyptic number.
12041324431 is a deficient number, since it is larger than the sum of its proper divisors (1).
12041324431 is an equidigital number, since it uses as much as digits as its factorization.
12041324431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 12041324431 its reverse (13442314021), we get a palindrome (25483638452).
The spelling of 12041324431 in words is "twelve billion, forty-one million, three hundred twenty-four thousand, four hundred thirty-one".
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