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12042321101053 is a prime number
BaseRepresentation
bin1010111100111101001001…
…0001011000000011111101
31120122020100001200210100121
42233033102101120003331
53034300133200213203
641340055502054541
72352012641310535
oct257172221300375
946566301623317
1012042321101053
113923135356481
121425a70b7a451
136947805c4909
142d8bcc54c4c5
1515d3ad5960bd
hexaf3d24580fd

12042321101053 has 2 divisors, whose sum is σ = 12042321101054. Its totient is φ = 12042321101052.

The previous prime is 12042321101039. The next prime is 12042321101099. The reversal of 12042321101053 is 35010112324021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10838073847129 + 1204247253924 = 3292123^2 + 1097382^2 .

It is a cyclic number.

It is not a de Polignac number, because 12042321101053 - 25 = 12042321101021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12042321101453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6021160550526 + 6021160550527.

It is an arithmetic number, because the mean of its divisors is an integer number (6021160550527).

Almost surely, 212042321101053 is an apocalyptic number.

It is an amenable number.

12042321101053 is a deficient number, since it is larger than the sum of its proper divisors (1).

12042321101053 is an equidigital number, since it uses as much as digits as its factorization.

12042321101053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 12042321101053 its reverse (35010112324021), we get a palindrome (47052433425074).

The spelling of 12042321101053 in words is "twelve trillion, forty-two billion, three hundred twenty-one million, one hundred one thousand, fifty-three".