Base | Representation |
---|---|
bin | 11011011000011001111111… |
… | …011101001110000011001111 |
3 | 120210101110111200100200211102 |
4 | 123120121333131032003033 |
5 | 111241013213420131112 |
6 | 1104042115311013315 |
7 | 34236243446514644 |
oct | 3330317735160317 |
9 | 523343450320742 |
10 | 120424431411407 |
11 | 35409795089602 |
12 | 1160b08a50a23b |
13 | 5226c8a553166 |
14 | 21a4805c8bdcb |
15 | ddc7b0d5abc2 |
hex | 6d867f74e0cf |
120424431411407 has 2 divisors, whose sum is σ = 120424431411408. Its totient is φ = 120424431411406.
The previous prime is 120424431411341. The next prime is 120424431411463. The reversal of 120424431411407 is 704114134424021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120424431411407 - 210 = 120424431410383 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120424431411307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60212215705703 + 60212215705704.
It is an arithmetic number, because the mean of its divisors is an integer number (60212215705704).
Almost surely, 2120424431411407 is an apocalyptic number.
120424431411407 is a deficient number, since it is larger than the sum of its proper divisors (1).
120424431411407 is an equidigital number, since it uses as much as digits as its factorization.
120424431411407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 86016, while the sum is 38.
Adding to 120424431411407 its reverse (704114134424021), we get a palindrome (824538565835428).
The spelling of 120424431411407 in words is "one hundred twenty trillion, four hundred twenty-four billion, four hundred thirty-one million, four hundred eleven thousand, four hundred seven".
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