Base | Representation |
---|---|
bin | 10001100001100111001… |
… | …100110000011001101111 |
3 | 11021010120021202122202112 |
4 | 101201213030300121233 |
5 | 124212422443140421 |
6 | 2321131421114235 |
7 | 153003141065114 |
oct | 21414714603157 |
9 | 4233507678675 |
10 | 1204322240111 |
11 | 424828565061 |
12 | 1754a50b897b |
13 | 8974abc3133 |
14 | 4240a5a090b |
15 | 214d93b445b |
hex | 1186733066f |
1204322240111 has 2 divisors, whose sum is σ = 1204322240112. Its totient is φ = 1204322240110.
The previous prime is 1204322240071. The next prime is 1204322240113. The reversal of 1204322240111 is 1110422234021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1204322240111 is a prime.
Together with 1204322240113, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1204322240113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 602161120055 + 602161120056.
It is an arithmetic number, because the mean of its divisors is an integer number (602161120056).
Almost surely, 21204322240111 is an apocalyptic number.
1204322240111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1204322240111 is an equidigital number, since it uses as much as digits as its factorization.
1204322240111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 1204322240111 its reverse (1110422234021), we get a palindrome (2314744474132).
The spelling of 1204322240111 in words is "one trillion, two hundred four billion, three hundred twenty-two million, two hundred forty thousand, one hundred eleven".
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