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12043315219679 is a prime number
BaseRepresentation
bin1010111101000000110110…
…0001101000110011011111
31120122022220100022020201222
42233100031201220303133
53034304202144012204
641340342253323555
72352046402214552
oct257201541506337
946568810266658
1012043315219679
1139235a5522517
1214260a9a965bb
136948ab552aa3
142d8c845a8699
1515d41a9b4abe
hexaf40d868cdf

12043315219679 has 2 divisors, whose sum is σ = 12043315219680. Its totient is φ = 12043315219678.

The previous prime is 12043315219603. The next prime is 12043315219693. The reversal of 12043315219679 is 97691251334021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12043315219679 - 28 = 12043315219423 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12043315219679.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12043315219699) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6021657609839 + 6021657609840.

It is an arithmetic number, because the mean of its divisors is an integer number (6021657609840).

Almost surely, 212043315219679 is an apocalyptic number.

12043315219679 is a deficient number, since it is larger than the sum of its proper divisors (1).

12043315219679 is an equidigital number, since it uses as much as digits as its factorization.

12043315219679 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2449440, while the sum is 53.

The spelling of 12043315219679 in words is "twelve trillion, forty-three billion, three hundred fifteen million, two hundred nineteen thousand, six hundred seventy-nine".