Base | Representation |
---|---|
bin | 1010111101000000110110… |
… | …0001101000111100000011 |
3 | 1120122022220100022021111021 |
4 | 2233100031201220330003 |
5 | 3034304202144021402 |
6 | 41340342253330311 |
7 | 2352046402216264 |
oct | 257201541507403 |
9 | 46568810267437 |
10 | 12043315220227 |
11 | 39235a5522975 |
12 | 14260a9a96997 |
13 | 6948ab553105 |
14 | 2d8c845a896b |
15 | 15d41a9b4d37 |
hex | af40d868f03 |
12043315220227 has 2 divisors, whose sum is σ = 12043315220228. Its totient is φ = 12043315220226.
The previous prime is 12043315220221. The next prime is 12043315220231. The reversal of 12043315220227 is 72202251334021.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12043315220227 - 231 = 12041167736579 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12043315220192 and 12043315220201.
It is not a weakly prime, because it can be changed into another prime (12043315220221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6021657610113 + 6021657610114.
It is an arithmetic number, because the mean of its divisors is an integer number (6021657610114).
Almost surely, 212043315220227 is an apocalyptic number.
12043315220227 is a deficient number, since it is larger than the sum of its proper divisors (1).
12043315220227 is an equidigital number, since it uses as much as digits as its factorization.
12043315220227 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 34.
Adding to 12043315220227 its reverse (72202251334021), we get a palindrome (84245566554248).
The spelling of 12043315220227 in words is "twelve trillion, forty-three billion, three hundred fifteen million, two hundred twenty thousand, two hundred twenty-seven".
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