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12043315220227 is a prime number
BaseRepresentation
bin1010111101000000110110…
…0001101000111100000011
31120122022220100022021111021
42233100031201220330003
53034304202144021402
641340342253330311
72352046402216264
oct257201541507403
946568810267437
1012043315220227
1139235a5522975
1214260a9a96997
136948ab553105
142d8c845a896b
1515d41a9b4d37
hexaf40d868f03

12043315220227 has 2 divisors, whose sum is σ = 12043315220228. Its totient is φ = 12043315220226.

The previous prime is 12043315220221. The next prime is 12043315220231. The reversal of 12043315220227 is 72202251334021.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12043315220227 - 231 = 12041167736579 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12043315220192 and 12043315220201.

It is not a weakly prime, because it can be changed into another prime (12043315220221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6021657610113 + 6021657610114.

It is an arithmetic number, because the mean of its divisors is an integer number (6021657610114).

Almost surely, 212043315220227 is an apocalyptic number.

12043315220227 is a deficient number, since it is larger than the sum of its proper divisors (1).

12043315220227 is an equidigital number, since it uses as much as digits as its factorization.

12043315220227 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 34.

Adding to 12043315220227 its reverse (72202251334021), we get a palindrome (84245566554248).

The spelling of 12043315220227 in words is "twelve trillion, forty-three billion, three hundred fifteen million, two hundred twenty thousand, two hundred twenty-seven".