Base | Representation |
---|---|
bin | 10001100001101101010… |
… | …010011101110010001101 |
3 | 11021010211101222220210121 |
4 | 101201231102131302031 |
5 | 124213130121300023 |
6 | 2321145510504541 |
7 | 153005521324312 |
oct | 21415522356215 |
9 | 4233741886717 |
10 | 1204424400013 |
11 | 4248801a132a |
12 | 175513365151 |
13 | 89766111a93 |
14 | 42419d94d09 |
15 | 214e3343d5d |
hex | 1186d49dc8d |
1204424400013 has 2 divisors, whose sum is σ = 1204424400014. Its totient is φ = 1204424400012.
The previous prime is 1204424399963. The next prime is 1204424400019. The reversal of 1204424400013 is 3100044244021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 785993952969 + 418430447044 = 886563^2 + 646862^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1204424400013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1204424400019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 602212200006 + 602212200007.
It is an arithmetic number, because the mean of its divisors is an integer number (602212200007).
Almost surely, 21204424400013 is an apocalyptic number.
It is an amenable number.
1204424400013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1204424400013 is an equidigital number, since it uses as much as digits as its factorization.
1204424400013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3072, while the sum is 25.
Adding to 1204424400013 its reverse (3100044244021), we get a palindrome (4304468644034).
The spelling of 1204424400013 in words is "one trillion, two hundred four billion, four hundred twenty-four million, four hundred thousand, thirteen".
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