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12044402204413 is a prime number
BaseRepresentation
bin1010111101000100111001…
…0100001001111011111101
31120122102201002122210110211
42233101032110021323331
53034313413431020123
641341042203232421
72352115341352345
oct257211624117375
946572632583424
1012044402204413
113924003058207
121426351b18711
13694a227c7617
142d8d48ab9d25
1515d48112940d
hexaf44e509efd

12044402204413 has 2 divisors, whose sum is σ = 12044402204414. Its totient is φ = 12044402204412.

The previous prime is 12044402204353. The next prime is 12044402204431. The reversal of 12044402204413 is 31440220444021.

It is a happy number.

Together with next prime (12044402204431) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10452722226489 + 1591679977924 = 3233067^2 + 1261618^2 .

It is a cyclic number.

It is not a de Polignac number, because 12044402204413 - 213 = 12044402196221 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12044402204473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6022201102206 + 6022201102207.

It is an arithmetic number, because the mean of its divisors is an integer number (6022201102207).

Almost surely, 212044402204413 is an apocalyptic number.

It is an amenable number.

12044402204413 is a deficient number, since it is larger than the sum of its proper divisors (1).

12044402204413 is an equidigital number, since it uses as much as digits as its factorization.

12044402204413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24576, while the sum is 31.

Adding to 12044402204413 its reverse (31440220444021), we get a palindrome (43484622648434).

The spelling of 12044402204413 in words is "twelve trillion, forty-four billion, four hundred two million, two hundred four thousand, four hundred thirteen".