Base | Representation |
---|---|
bin | 10110011100010011… |
… | …00111111110100101 |
3 | 1011002200111110211001 |
4 | 23032021213332211 |
5 | 144133413023013 |
6 | 5311322313301 |
7 | 604401051064 |
oct | 131611477645 |
9 | 34080443731 |
10 | 12048564133 |
11 | 5123111621 |
12 | 2403058831 |
13 | 11a02394b8 |
14 | 8242601db |
15 | 4a7b64ddd |
hex | 2ce267fa5 |
12048564133 has 2 divisors, whose sum is σ = 12048564134. Its totient is φ = 12048564132.
The previous prime is 12048564131. The next prime is 12048564233. The reversal of 12048564133 is 33146584021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11726074369 + 322489764 = 108287^2 + 17958^2 .
It is a cyclic number.
It is not a de Polignac number, because 12048564133 - 21 = 12048564131 is a prime.
Together with 12048564131, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 12048564092 and 12048564101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12048564131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6024282066 + 6024282067.
It is an arithmetic number, because the mean of its divisors is an integer number (6024282067).
Almost surely, 212048564133 is an apocalyptic number.
It is an amenable number.
12048564133 is a deficient number, since it is larger than the sum of its proper divisors (1).
12048564133 is an equidigital number, since it uses as much as digits as its factorization.
12048564133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 69120, while the sum is 37.
The spelling of 12048564133 in words is "twelve billion, forty-eight million, five hundred sixty-four thousand, one hundred thirty-three".
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