Base | Representation |
---|---|
bin | 1010111101011011000011… |
… | …1101101011110001101111 |
3 | 1120200000001202200011211011 |
4 | 2233112300331223301233 |
5 | 3034413110132203031 |
6 | 41343504433010051 |
7 | 2352415650611314 |
oct | 257266075536157 |
9 | 46600052604734 |
10 | 12050352225391 |
11 | 3926586752017 |
12 | 14275326b3927 |
13 | 6954604146ac |
14 | 2d9350dd8d0b |
15 | 15d6cd68d6b1 |
hex | af5b0f6bc6f |
12050352225391 has 2 divisors, whose sum is σ = 12050352225392. Its totient is φ = 12050352225390.
The previous prime is 12050352225347. The next prime is 12050352225433. The reversal of 12050352225391 is 19352225305021.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12050352225391 - 219 = 12050351701103 is a prime.
It is a super-3 number, since 3×120503522253913 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12050352205391) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6025176112695 + 6025176112696.
It is an arithmetic number, because the mean of its divisors is an integer number (6025176112696).
Almost surely, 212050352225391 is an apocalyptic number.
12050352225391 is a deficient number, since it is larger than the sum of its proper divisors (1).
12050352225391 is an equidigital number, since it uses as much as digits as its factorization.
12050352225391 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162000, while the sum is 40.
The spelling of 12050352225391 in words is "twelve trillion, fifty billion, three hundred fifty-two million, two hundred twenty-five thousand, three hundred ninety-one".
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