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1205253474431 is a prime number
BaseRepresentation
bin10001100010011110101…
…101001000100001111111
311021012222012001021002112
4101202132231020201333
5124221324342140211
62321404044444235
7153035206333016
oct21423655104177
94235865037075
101205253474431
114251661901a6
12175704b4967b
1389868b04566
144249812ba7d
152154101088b
hex1189eb4887f

1205253474431 has 2 divisors, whose sum is σ = 1205253474432. Its totient is φ = 1205253474430.

The previous prime is 1205253474413. The next prime is 1205253474449. The reversal of 1205253474431 is 1344743525021.

Together with previous prime (1205253474413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (1205253474413) and next prime (1205253474449).

It is a cyclic number.

It is not a de Polignac number, because 1205253474431 - 234 = 1188073605247 is a prime.

It is a super-2 number, since 2×12052534744312 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1205253470431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 602626737215 + 602626737216.

It is an arithmetic number, because the mean of its divisors is an integer number (602626737216).

Almost surely, 21205253474431 is an apocalyptic number.

1205253474431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1205253474431 is an equidigital number, since it uses as much as digits as its factorization.

1205253474431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 403200, while the sum is 41.

Adding to 1205253474431 its reverse (1344743525021), we get a palindrome (2549996999452).

The spelling of 1205253474431 in words is "one trillion, two hundred five billion, two hundred fifty-three million, four hundred seventy-four thousand, four hundred thirty-one".