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120795045382967 is a prime number
BaseRepresentation
bin11011011101110011001001…
…110001010100101100110111
3120211200220010101221011002112
4123131303021301110230313
5111313101223104223332
61104524251110401235
734305103555346444
oct3335631161245467
9524626111834075
10120795045382967
1135541988aa888a
121166aa8036021b
135252c01a77497
1421b87233889cb
15de72529a7db2
hex6ddcc9c54b37

120795045382967 has 2 divisors, whose sum is σ = 120795045382968. Its totient is φ = 120795045382966.

The previous prime is 120795045382951. The next prime is 120795045382969. The reversal of 120795045382967 is 769283540597021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 120795045382967 - 24 = 120795045382951 is a prime.

Together with 120795045382969, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 120795045382897 and 120795045382906.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120795045382969) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60397522691483 + 60397522691484.

It is an arithmetic number, because the mean of its divisors is an integer number (60397522691484).

It is a 1-persistent number, because it is pandigital, but 2⋅120795045382967 = 241590090765934 is not.

Almost surely, 2120795045382967 is an apocalyptic number.

120795045382967 is a deficient number, since it is larger than the sum of its proper divisors (1).

120795045382967 is an equidigital number, since it uses as much as digits as its factorization.

120795045382967 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 228614400, while the sum is 68.

The spelling of 120795045382967 in words is "one hundred twenty trillion, seven hundred ninety-five billion, forty-five million, three hundred eighty-two thousand, nine hundred sixty-seven".