Base | Representation |
---|---|
bin | 10110100000111111… |
… | …11100010010000111 |
3 | 1011012102122102222222 |
4 | 23100133330102013 |
5 | 144224010001103 |
6 | 5315251042555 |
7 | 605360016563 |
oct | 132037742207 |
9 | 34172572888 |
10 | 12087968903 |
11 | 5143385a4a |
12 | 24142a045b |
13 | 11a845512a |
14 | 82959a6a3 |
15 | 4ab34a638 |
hex | 2d07fc487 |
12087968903 has 2 divisors, whose sum is σ = 12087968904. Its totient is φ = 12087968902.
The previous prime is 12087968899. The next prime is 12087968953. The reversal of 12087968903 is 30986978021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12087968903 - 22 = 12087968899 is a prime.
It is a super-2 number, since 2×120879689032 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12087968953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6043984451 + 6043984452.
It is an arithmetic number, because the mean of its divisors is an integer number (6043984452).
Almost surely, 212087968903 is an apocalyptic number.
12087968903 is a deficient number, since it is larger than the sum of its proper divisors (1).
12087968903 is an equidigital number, since it uses as much as digits as its factorization.
12087968903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1306368, while the sum is 53.
The spelling of 12087968903 in words is "twelve billion, eighty-seven million, nine hundred sixty-eight thousand, nine hundred three".
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