Base | Representation |
---|---|
bin | 10001100110110111011… |
… | …010001001110010011111 |
3 | 11021200010101122200201201 |
4 | 101212313122021302133 |
5 | 124311001000142133 |
6 | 2323503240020331 |
7 | 153263002632442 |
oct | 21466732116237 |
9 | 4250111580651 |
10 | 1209962896543 |
11 | 427162569795 |
12 | 1765ba1616a7 |
13 | 8a1396b3b6b |
14 | 427c378d659 |
15 | 217196b9d7d |
hex | 119b7689c9f |
1209962896543 has 2 divisors, whose sum is σ = 1209962896544. Its totient is φ = 1209962896542.
The previous prime is 1209962896531. The next prime is 1209962896609. The reversal of 1209962896543 is 3456982699021.
It is a weak prime.
It is an emirp because it is prime and its reverse (3456982699021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1209962896543 - 221 = 1209960799391 is a prime.
It is a super-2 number, since 2×12099628965432 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1209962896523) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 604981448271 + 604981448272.
It is an arithmetic number, because the mean of its divisors is an integer number (604981448272).
Almost surely, 21209962896543 is an apocalyptic number.
1209962896543 is a deficient number, since it is larger than the sum of its proper divisors (1).
1209962896543 is an equidigital number, since it uses as much as digits as its factorization.
1209962896543 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 50388480, while the sum is 64.
The spelling of 1209962896543 in words is "one trillion, two hundred nine billion, nine hundred sixty-two million, eight hundred ninety-six thousand, five hundred forty-three".
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