Base | Representation |
---|---|
bin | 10110100010011011… |
… | …10101110101100000 |
3 | 1011020021021202002122 |
4 | 23101031311311200 |
5 | 144240100013440 |
6 | 5320401003412 |
7 | 605564212124 |
oct | 132115656540 |
9 | 34207252078 |
10 | 12100001120 |
11 | 514a153a29 |
12 | 2418323568 |
13 | 11aaaa899c |
14 | 82b00d584 |
15 | 4ac4257b5 |
hex | 2d1375d60 |
12100001120 has 48 divisors (see below), whose sum is σ = 28977873120. Its totient is φ = 4773694464.
The previous prime is 12100001101. The next prime is 12100001129. The reversal of 12100001120 is 2110000121.
12100001120 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (8).
It is a junction number, because it is equal to n+sod(n) for n = 12100001098 and 12100001107.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12100001129) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 506300 + ... + 529659.
It is an arithmetic number, because the mean of its divisors is an integer number (603705690).
Almost surely, 212100001120 is an apocalyptic number.
12100001120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12100001120 is an abundant number, since it is smaller than the sum of its proper divisors (16877872000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12100001120 is a wasteful number, since it uses less digits than its factorization.
12100001120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1036047 (or 1036039 counting only the distinct ones).
The product of its (nonzero) digits is 4, while the sum is 8.
Adding to 12100001120 its reverse (2110000121), we get a palindrome (14210001241).
Subtracting from 12100001120 its reverse (2110000121), we obtain a palindrome (9990000999).
It can be divided in two parts, 12100001 and 120, that added together give a palindrome (12100121).
The spelling of 12100001120 in words is "twelve billion, one hundred million, one thousand, one hundred twenty".
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