12100011000013 has 2 divisors, whose sum is σ = 12100011000014. Its totient is φ = 12100011000012.

The previous prime is 12100010999863. The next prime is 12100011000151. The reversal of 12100011000013 is 31000011000121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6411413933929 + 5688597066084 = 2532077^2 + 2385078^2 .

It is an emirp because it is prime and its reverse (31000011000121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12100011000013 - 2¹⁷ = 12100010868941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12100011004013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050005500006 + 6050005500007.

It is an arithmetic number, because the mean of its divisors is an integer number (6050005500007).

Almost surely, 2^{12100011000013} is an apocalyptic number.

It is an amenable number.

12100011000013 is a deficient number, since it is larger than the sum of its proper divisors (1).

12100011000013 is an equidigital number, since it uses as much as digits as its factorization.

12100011000013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 12100011000013 its reverse (31000011000121), we get a palindrome (43100022000134).

The spelling of 12100011000013 in words is "twelve trillion, one hundred billion, eleven million, thirteen", and thus it is an aban number.