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121000202220110 = 2512100020222011
BaseRepresentation
bin11011100000110010001110…
…000100100011001001001110
3120212102111200010201022021012
4123200302032010203021032
5111324431403232020420
61105202420413405222
734325655544605203
oct3340621604431116
9525374603638235
10121000202220110
1135610996759064
12116a2796a99812
135269368579185
1421c46262b5caa
15dec75da13dc5
hex6e0c8e12324e

121000202220110 has 8 divisors (see below), whose sum is σ = 217800363996216. Its totient is φ = 48400080888040.

The previous prime is 121000202220109. The next prime is 121000202220127. The reversal of 121000202220110 is 11022202000121.

121000202220110 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6050010110996 + ... + 6050010111015.

It is an arithmetic number, because the mean of its divisors is an integer number (27225045499527).

Almost surely, 2121000202220110 is an apocalyptic number.

121000202220110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

121000202220110 is a deficient number, since it is larger than the sum of its proper divisors (96800161776106).

121000202220110 is a wasteful number, since it uses less digits than its factorization.

121000202220110 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12100020222018.

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 121000202220110 its reverse (11022202000121), we get a palindrome (132022404220231).

The spelling of 121000202220110 in words is "one hundred twenty-one trillion, two hundred two million, two hundred twenty thousand, one hundred ten".

Divisors: 1 2 5 10 12100020222011 24200040444022 60500101110055 121000202220110