Base | Representation |
---|---|
bin | 11011100000110010001110… |
… | …000100100011001001001110 |
3 | 120212102111200010201022021012 |
4 | 123200302032010203021032 |
5 | 111324431403232020420 |
6 | 1105202420413405222 |
7 | 34325655544605203 |
oct | 3340621604431116 |
9 | 525374603638235 |
10 | 121000202220110 |
11 | 35610996759064 |
12 | 116a2796a99812 |
13 | 5269368579185 |
14 | 21c46262b5caa |
15 | dec75da13dc5 |
hex | 6e0c8e12324e |
121000202220110 has 8 divisors (see below), whose sum is σ = 217800363996216. Its totient is φ = 48400080888040.
The previous prime is 121000202220109. The next prime is 121000202220127. The reversal of 121000202220110 is 11022202000121.
121000202220110 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6050010110996 + ... + 6050010111015.
It is an arithmetic number, because the mean of its divisors is an integer number (27225045499527).
Almost surely, 2121000202220110 is an apocalyptic number.
121000202220110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
121000202220110 is a deficient number, since it is larger than the sum of its proper divisors (96800161776106).
121000202220110 is a wasteful number, since it uses less digits than its factorization.
121000202220110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12100020222018.
The product of its (nonzero) digits is 32, while the sum is 14.
Adding to 121000202220110 its reverse (11022202000121), we get a palindrome (132022404220231).
The spelling of 121000202220110 in words is "one hundred twenty-one trillion, two hundred two million, two hundred twenty thousand, one hundred ten".
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