1210002131111 has 2 divisors, whose sum is σ = 1210002131112. Its totient is φ = 1210002131110.

The previous prime is 1210002131083. The next prime is 1210002131113. The reversal of 1210002131111 is 1111312000121.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1210002131111 is a prime.

It is a super-3 number, since 3×1210002131111³ (a number of 37 digits) contains 333 as substring.

Together with 1210002131113, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1210002131113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605001065555 + 605001065556.

It is an arithmetic number, because the mean of its divisors is an integer number (605001065556).

Almost surely, 2^{1210002131111} is an apocalyptic number.

1210002131111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1210002131111 is an equidigital number, since it uses as much as digits as its factorization.

1210002131111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 1210002131111 its reverse (1111312000121), we get a palindrome (2321314131232).

The spelling of 1210002131111 in words is "one trillion, two hundred ten billion, two million, one hundred thirty-one thousand, one hundred eleven".