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121000423 is a prime number
BaseRepresentation
bin1110011011001…
…01000111100111
322102200110101011
413031211013213
5221434003143
620001243051
72666325625
oct715450747
9272613334
10121000423
1162335455
1234633487
131c0b73ab
14120da515
15a951e9d
hex73651e7

121000423 has 2 divisors, whose sum is σ = 121000424. Its totient is φ = 121000422.

The previous prime is 121000421. The next prime is 121000427. The reversal of 121000423 is 324000121.

It is a weak prime.

It is an emirp because it is prime and its reverse (324000121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121000423 - 21 = 121000421 is a prime.

It is a super-2 number, since 2×1210004232 = 29282204732357858, which contains 22 as substring.

Together with 121000421, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121000421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60500211 + 60500212.

It is an arithmetic number, because the mean of its divisors is an integer number (60500212).

Almost surely, 2121000423 is an apocalyptic number.

121000423 is a deficient number, since it is larger than the sum of its proper divisors (1).

121000423 is an equidigital number, since it uses as much as digits as its factorization.

121000423 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 121000423 is about 11000.0192272559. The cubic root of 121000423 is about 494.6093206865.

Adding to 121000423 its reverse (324000121), we get a palindrome (445000544).

The spelling of 121000423 in words is "one hundred twenty-one million, four hundred twenty-three", and thus it is an aban number.